martis
1
Hello,
I encountered an issue while projecting a TH3 into a TH1. It basically works, but when I use the “e” option the number of entries changes.
This is the straight output:
root [8] h1_3DPtPosMu->GetEntries()
(double) 527930.000000
root [9] h1_3DPtPosMu->ProjectionZ(“hpos_0”,-1,-1,-1,-1)->GetEntries()
(double) 527930.000000
root [10] h1_3DPtPosMu->ProjectionZ(“hpos_e”,-1,-1,-1,-1)->GetEntries()
(double) 527930.000000
I would expect the “e” option has no effect on the number of entries in the projected.
Cheers
Salva
martis
2
Apologize for the spam. The screen capture I sent was wrong. It was not showing the effect of the “e” option. Please read the one here below.
root [1] h1_3DPtPosMu->GetEntries()
(double) 527930.000000
root [2] h1_3DPtPosMu->ProjectionZ(“hpos_0”,-1,-1,-1,-1)->GetEntries()
(double) 527930.000000
root [3] h1_3DPtPosMu->ProjectionZ(“hpos_e”,-1,-1,-1,-1,“e”)->GetEntries()
(double) 527566.000000
Cheers
Salva
couet
3
I guess @moneta can help you
moneta
4
Hi,
Is the histogram weighted ? In this case the effective entries will be computed and by using option “e” the effective entries will be different
Lorenzo
martis
5
Hi
yes, the histogram is weighted, but in this test all weights sould
be 1.
However, now I am confused about what the "e" option does.
Cheers
Salva
system
Closed
6
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