FFT output x axis

[nazar_sokour]

Dear colleagues,

For example, if my histogram has N bins from x_min to x_max, so the width of one bin is equal to N / (x_max - x_min). The output histogram after FFT is same size N, but what about x_limits? As I understand, it should be from -1 / [N / (x_max - x_min)] to 1 / [N / (x_max - x_min)], right?

Best,
Nazar

[jalopezg]

Hi @nazar_sokour; perhaps @couet can help here.

Cheers,
J.

[couet]

@nazar_sokour

the width of one bin is equal to N / (x_max - x_min).

It is the inverse: (x_max - x_min)/N

@nazar_sokour

The output histogram after FFT is same size N, but what about x_limits? As I understand, it should be from -1 / [N / (x_max - x_min)] to 1 / [N / (x_max - x_min)], right?

@moneta will know better.

[nazar_sokour]

Oh, yes, of course: bin’s width is W = (x_max - x_min) / N. I mean, I guessed that x limits is from (-1 / W) to (1 / W). Thanks.
Hope, someone helps.