Storing efficiency numbers into array

Newbie
1

Hi all,
I am trying to store obtained values into an array, for this I thought it’s better to use vector, however when I call it, just to check - cout << digitArray[0] << endl; I get “-nan” output. The value I want to fill this array with is there and is “double_t” .

So, I am doing following. I am filling two histograms and taking the fraction of their integrals, then I have a number and I want to store that number in an array (or vector). Why isn’t my solution working?..

2

Hi,

suppose int1 is the integral of your first histogram and int2 is the one of your second histogram. Then you store their ratio in a vector:

        constexpr Double_t int1 = 8.5, int2 = 34.1;
        std::vector<Double_t> myVec = {int1/int2};
        printf("My fraction is %f\n", myVec.at(0));
1 Like
3

Thanks @yus! It worked perfectly fine! So, now if I want to build a TGraph with these numbers, I can’t do it since I used a vector, not an array, right? Or is it possible to build TGraph from vector entries?

4

You can use

std::vector<double> x = {...};
std::vector<double> y = {...};
assert(x.size() == y.size() && "x and y vectors must have the same size!");
TGraph g(TGraph(x.size(),&x[0],&y[0]);
5

Hi,
Thanks for your reply. This will build TGraph with only first numbers of the vector, right ? How can I make so that it builds with all numbers in the vector?

I tried something like : for(Double_t x : myFirstVec && Double_t y : mySecondVec) {
TGraph g(TGraph(x.size(), x, y);
}

but well, it does not really work. Since i cannot draw it outside the for loop

6

No, this is for all of them. Check this out in ROOT prompt:

std::vector<double> x = {0., 1., 2., 3., 4.};
std::vector<double> y = {0., 1., 2., 3., 4.};
TGraph g(TGraph(x.size(),&x[0],&y[0]));
g.Draw("AC*");
7

Thank you so much! It worked perfectly!:slight_smile: