Root macro with external functions

ROOT
1

Dear experts,
I have my root macro [1], and I have a file.cc in which I have several function [2]. As I have several
function in my file.cc, I wonder how to call them in the root macro, indeed using “myfunc();” in [3] give me the error message[4]. Do you know what is wrong?
Regards

[4]
error: use of undeclared identifier ‘myfunc’

[3] root.cc
#include "myfunc.cc"
void root(){
myfunc();
cout<<max();
}

[2] myfunc.cc
double max(){
…
}
bool pass(){
…
}

[1] root.cc
#include "myfunc.cc"
void root(){
cout<<max();
}

2

You do not define “myfunc()” anywhere.

3

Dear pepe,
yes I used “myfunc();” in [1], but I got the error message in [2]:
Do you know what is wrong?
Regards

[2]
error: use of undeclared identifier ‘myfunc’

[1] root.cc
#include “myfunc.cc” //include func.cc here!!
void root(){
myfunc(); //call func here!!
cout<<max();
}

4

Where it the definition:
myfunc() {
std::cout << “… myfunc called …” << std::endl;
}

5

Dear pepe,
may I explain again. In myfunc.cc, I have several functions [1] (I actually want to put all my functions in a single file). Now, how can I call one of them in a root macro?

Regards

[2] root.cc
#include "myfunc.cc"
void root(){

//how to call func1() from myfunc.cc

}

[1] myfunc.cc
double func1(){ … }
double func2(){ … }
…

6

Use simply (“root.cc”):
#include "myfunc.cc"
void root() {
double x, y;
x = func1();
y = func2();
std::cout << "x = " << x << " and y = " << y << std::endl;
}
Then:
root [0] .x root.cc
or:
root [0] .L root.cc
root [1] root()
or:
root -q -l root.cc

7

Yes, but when I do that I have:
error: use of undeclared identifier 'myfunc’
myfunc();

Do you know what is wrong? I have ROOT 6.06/01
Regards

8

Dear pepe,
for some reason it’s working now (the way you advised)… Thank you very much for your help.
Regards