Return Value of TVectorT::operator[]

ROOT
1

Hello together,

i have a problem with TVectorT.

In my program i am working with a std::vector. I need to save this list to a root file. I could not find a way to save this vector directly (is it possible?), so i converted the std::vector to a TVectorT ( i already read that this is not the root equivalent to the std::vector, is there any?):

[code]
TVectorD charge_root(10);
std::vector charge;

// fill the std::vector with 10 elements

for(int bx=0; bx < 10;bx++)
{
	charge_root[bx] = charge.at(bx);
}[/code]

But when i load the list and try to convert it back, i get an error. This is the way i try it:

		for(int bxx=0; bxx < 10;bxx++)
		{
		      charge.push_back(charge_root[bxx]);
		}

The error i get from the compiler:
no matching function for call to ‘std::vector<double, std::allocator >::push_back(TVectorT&)’
/usr/include/c++/4.3/bits/stl_vector.h:686: note: candidates are: void std::vector<_Tp, _Alloc>::push_back(const _Tp&) [with _Tp = double, _Alloc = std::allocator]

But the operator[] should give as a return value a double&, and not a TVectorT. What do i wrong?

I am using Root 5.28/00 on a Suse11.1 (what information else?)

Thank you for reading

Greeting

Simone

2

Hi Simone,

I could not find a way to save this vector directly (is it possible?)Yes, it is. It should work as any other object. (you may have to force the loading of the dictionary for vectors via gROOT->ProcessLine("#include "):wink:

, so i converted the std::vector to a TVectorT ( i already read that this is not the root equivalent to the std::vector, is there any?)The closest is TArrayF and TArrayD.

Cheers,
Philippe.