Dear all, I am trying to calculate value of a integral with definite bounds but the integrand is another integral, and one of the bounds of this second integral is the variable of the first integral. I am attaching representative picture. \int_{9.5}^{10.5}dx\ x \int_{1}^0 dy \ y How I can write t…

Dear @Wile_E_Coyote , thank you a lot for always replying. I have done the change of variables but actually it couldn’t solve my problem as far as understand. Maybe the representative function was too easy. My function is bit more complicated \int_{9.5}^{10.5}da \frac{1}{x} \int_{0}^{1}dt\ a*t*sin(x…

ROOT Manual → Functional parts → Mathematical libraries → MathCore library → Numerical integration

Dear @Wile_E_Coyote , I have checked all of thet page. But I think it doesn’t cover my problem. I am sorry if I am missing something. But the thing is, I cannot write my function as \int_{0}^1\int_{0}^1\int_{0}^1\int_{0}^1dxdydzdt\ x * y * z * t it is more of the form \int_{9.5}^{10.5}da \frac{1}…

The integral over “dl” is just “-a/2.” and the integral over “dk” is just “-a*t/2.”. Possibly you could also “simplify” the remaining integrals → WolframAlpha BTW. I don’t know what kind of variable “x” is ( “sph_bessel” expects an “unsigned int” as the first parameter and a non-negative “double” …

Thank you a lot, but the thing is that integral I have written over here is representative. It is actually quite complicated. I cannot perform these integrals by hand easily, WolframAlpha exceeds the maximum integration time, and I have tried over Mathematica too but the result is too ugly to type t…

Just for completeness of this thread, see also: “Integral with dependent bounds”

Home | News | Documentation | Download

ROOT Forum

Double integration with dependent bounds

ROOT

Wile_E_Coyote March 14, 2023, 10:47am 2

C++ doubts in global variables and numerical integration ROOT

See the old “Boundary integral” and " Non-rectangular region integration" threads.

show post in topic

Home
Categories
Guidelines
Terms of Service
Privacy Policy

Powered by Discourse, best viewed with JavaScript enabled