Const char* to char*

ROOT
1

Hi

Can anybody tell me why does it works :

#include
void sample()
{
string a=“blabla”;
char *b;
b=a.c_str(); // ???

cout<<b<<endl;
}

I’m not a guru of c++, but shouldn’t be a warning while convert from const char* to char* ?

Regards
jimmij

2

Hi,

You are indeed correct. However note that CINT is error checking is in general intentionally more relaxed. This error will be properly caught be
the compiler.

Cheers,
Philippe.